**Problem 1:** A person leaves a place A to place B at 9 AM and reaches place B at 2 pm. Another person starts from point B at 11 AM and reaches point A at 2 PM. Find the ratio of distance covered by them at the time they meet each other?

Solution:

The time gap between 9AM-2PM=5hours

The time gap between 11AM-2PM=3hours

A B

T 5 3

S 3 5

Distance=Speed*Time=5*3=15

In two hours the distance traveled by A is 6km

15-6=9

**Problem 2**: Two guns were fired from the same place at an interval of 10min and 30 sec but a person on the train approaching the hear the second shot 10 min after the first. The speed of the train (in km/hr) supposing that the speed of sound travels at 330m/s is?

Solution:

10*60*S=30*330

Shortcut:

less time time difference

10min 30sec

T=600sec 30sec

S=330m/s ?