**Problem 1:** The quantity of water in 120 lit of milk and water is only 25% the milk man sold 20 liters of the mixture in this mixture and added 16.2 liters of pure milk and 3.8 liters of water in the remaining mixture. What is the percentage of water in the new mixture?

Solution: Total quantity=120

25%=

120-30=90

W : M

30 90

1 : 3

A milk man sold 20 liters of mixture so 120-20=100

Water =

100-25=75

3.8 liters of water is added to remaining mixture=25+3.8=28.8

16.2 liters of water is added to remaining mixture=16.2+75=91.2

%

**Problem 2:** In a bag there are 25p, 50p and 1r coins are there in the ratio 2:1:3. If their total is Rs.240 in all, how many 25p, 50p and 1 RS coins respectively are there in the bag?

Solution:

25 50 1

2 : 1 : 3

50p 50p 3RS

50P+50P+3RS=4

4———->240

2———–>?

1————>?

3————->?

**Problem 3:** Zinc and copper are in the ratio 2:1 in 75 kg of an alloy. The amount of copper to be further added to the alloy so as to make the ratio of zinc and copper 1:2?

Solution:

75-50=25

Zinc : Copper

50 : 25 + 75

50 : 100

1 : 2

100-25=75

75 kg of copper is added to get 1:2 ratio

**Problem 4:** A mixture contains alcohol and water in the ratio of 4:3 if 5 liters of water is added to the mixture the ratio becomes 4:5. Find the quantity of alcohol in the given mixture?

Solution:

Alcohol : water

4 : 3

4 : 5

2—————->5

4—————–>?

**Problem 5:** An perfume production company prepares perfume by mixing it water. The new mixture of 340 liters contains perfume and water in the ratio 27:7 later the company decides to liquefy the mixture to perform anew mixture containing perfume and water in the ratio of 3:1. How much water must they have to add in the previous mixture?

Solution:

Perfume=

340-270=70

Perfume : Water

270 : 70 + 20

270 : 90

3 : 1

20 liters of water is added to get the mixture of 3:1