Problem 1: The ratio of the radii of two circles is 5:6. If the area of the larger circle is 1296cm2, then what is the area of the smaller circle?
Problem 2: How many 2cm × 2cm size stickers can be cut from 9cm × 16cm size paper?
Problem 3: What is the area of the largest triangle that can be constructed inside a semicircle with radius Rcm?
Problem 4: How much distance a wheel of a diameter 1.26m will cover in 500 revolutions?
Diameter = =
Problem 1: Find the total surface area of a tetrahedron, length of whose sides are 6 cm?
Total surface area =
Problem 2: If the radius and height of the cylinder are 7cm and 6cm respectively then find the curved surface area of the cylinder?
Curved surface area = =
Problem 3: Ratio between height and radius of a right circular cone is 3: 1 and its volume is 1078cm3. Find the height of the cone.
h : r = 3 : 1
Height = 3*x = 3*7 = 21
Problem 4: If the volume of a sphere is numerically equal to its surface area then its diameter is?
Diameter = 2r =2*3 = 6
Problem 5: The diameters of two solid iron spheres are 4cm and 8cm respectively. These two spheres are melted to make a new solid cone whose radius is 6cm. Find its height?
Radius of first sphere = 2
Radius of second sphere = 4
v1+v2 = v3
Problem 1: The base of a right prism is a triangle. If the lengths of the sides are 5cm., 12cm. and 13cm. and volume of the prism is 450cm3, then the total surface area of the prism is?
Volume =Area * Height
450 = 30*h
Lateral surface area = Perimeter of base * Height
=30*15 = 450
Total surface area of prism =Lateral surface area+2(area of base)
450 + 2*30 =
Problem 2: Find the total surface area of the cube of side 3.5 cm?
Total surface area = = = 73.5
Problem 3: The diagonal of a cube is m. Find its volume?
Problem 3: A cuboidal brick has a length, breadth, and height of 25cm, 15cm and 5cm respectively. Find its total surface area.
Total surface area of cuboid = 2(lb+bh+lh)
= 2*575 = 1150
Problem 4: The base of a right pyramid is a square of side 40cm. If the volume of the pyramid is 8000cm3, then its height is?
Area of base = Area of square = 40*40 = 1600
h = 15
Problem 1: The area of the largest triangle that can be inscribed in a semicircle of radius 6m is?
Problem 2: The base and altitude of a right-angled triangle are 12cm and 16cm respectively the perpendicular distance of its hypotenuse from the opposite vertex is?
Problem 1: Radius of a circle is 14cm. and the angle at the center formed by a sector is 45 degrees. Find the area of the sector?
Area of a sector =
Problem 2: A rectangular sheet of 30 m × 20 m dimension is cut from its every corner as a quadrant of radius 3.5m. Find the area of remaining portion?
4 sectors = 1 circle
Area of rectangle = 30*20=600
Problem 3: Smaller diagonal of a rhombus is equal to the length of its sides. If the length of each side is 4 cm, then what is the area (in cm2) of an equilateral triangle with side equal to the bigger diagonal of the rhombus?
Area of equilateral triangle =