**Problem 1:** Ram got married 10 years ago. His present age is times of the age at the time of marriage. Ram’s sister was 4 years younger to him at the time of his marriage. Find out the present age of Ram’s sister?

Solution:

——->

R M

4 3

1——–>10

4———>?4*10=40

3———>?3*10=30

40-4=36 is the present age of Ram’s sister

**Problem 2:** If the two digits of the age of Arun are reversed then the new age so obtained is the age of his wife. 1/11 part of the sum of their ages is equal to the difference between their ages. If Arun is older than his wife then find the difference between their ages?

Solution:

Assume age of Arun =10x+y

Age of his wife = 10y+x

A=54 w = 45

Difference between the ages is 9

**Problem 3:** Arun’s brother is 3 years elder to him. his father was 28 years of age when his sister was born while his mother was 26 years of age when he was born, The ages of Arun’s father when his brother was born?

Solution:

Father age =28——->28+4=32

Mother age = 26——>26+4=30

Sister age=0——–>0+4 = 4

brother age = 0

The age of Arun’s father when the brother born is 32

**Problem 4:** If 6 years are subtracted from the present age of Randheer and the remainder is divided by 18 then the present age of his grandson Anup is obtained. If the Anup is 2 years younger to Mahesh whose age is 5 years, then whats the age of Randheer?

Solution:

Age of mahesh is= 5

Age of Anup is = 5-3 =2

R= 54+6 =60