**Problem 1:** The present ratio of the age of A and B is 3:5. If the sum of the present age of A and B is 48 years. Find the age of B before 5 years?

Solution:

A : B

3 : 5

8——->48

1———>?

5——–>6*5=30

Age of B before 5 years = 30-5=25

**Problem 2:** A man’s age is 125% of what it was 10 years ago, but 83% of what it will be after 10 years. What is his present age?

Solution:

125%——–>

4 is 10 years ago age and 5 is present age

5-4 = 1

1——–>10

5———->?5*10=50

4———–>?4*10=10

%=

5 is the present age and 6 is after 10 years

6-5=1

1——–>10

5———->?5*10=50

6———–>?6*10=60

hence the present age is 50 years

**Problem 3:** Father is aged three times more than his son. After 8 years, he would be two and half times of son’s age. After 16 years, how many times would he be the son’s age?

Solution:

F = 3*S

(3-1=2) *3

(5-2=3) *2

F : S

9 : 3

10 : 4

10-9=1

1——>8

9——>?9*8=72

3——–>?3*8=24

further 16 years

72+16=88

24+16=40

Fathers age is 2.2 times then the son’s age.