# Mensuration part 7

Problem 1: The perimeter of an isosceles triangle is 32 cm and each of the equal sides is 5/6 times of the base. What is the area (in cm2) of the triangle?

Solution:

2a+b=32

$2\times&space;\frac{5}{6}b+b=32$

$\frac{10b+6b}{6}=32$

b=12

2a=32-12=20

a=10

Area =$\frac{b}{4}\sqrt{4\times&space;10^{2}-12^{2}}$

$\frac{12}{4}\times&space;16=48$

Problem 2: Sides of a parallelogram are in the ratio 5 : 4. Its area is 1000 sq. units. Altitude on the greater side is 20 units. Altitude on the smaller side is?

Solution:

$h_{1}\times&space;b=h_{2}\times&space;l$

5x*20=4x*h

Height =25