# Mensuration Part 12

Problem 1: The area of the largest triangle that can be inscribed in a semicircle of radius 6m is?

Solution:

$\frac{1}{2}\times&space;b\times&space;h=\frac{1}{2}\times&space;2r\times&space;r$

$r^{2}=36m^{2}$

Problem 2: The base and altitude of a right-angled triangle are 12cm and 16cm respectively the perpendicular distance of its hypotenuse from the opposite vertex is?

Solution:

$\frac{1}{2}\times&space;12\times&space;16=\frac{1}{2}\times&space;20\times&space;h$

=9.6$m^{2}$