**Problem 1:** From a point on a circular track 5km long A, B, C started running in the same direction at the same time will speed of km/hr, 3km/hr,2km/hr then on the starting point all three will meet again?

Solution :

L.C.M of time A,B,C

T =

**Problem 2:** A man covered a certain distance at some speed, if he had move 3km/h faster, he would have taken 40min less. If he moved 2km/h slower, he would have taken 40min more. Find the distance in km?

Solution:

+3 -40

-2 +40

Cross multiply +3 * +40 = 120

-2 * -40 = 80

120:80 = 3:2

1———> 5

3——–>?

2———->?

**Problem 3:** “A” leaves Mumbai at 6 AM and reaches Bangalore at 10 AM. “B” leaves Bangalore at 8 AM and reaches Mumbai at 11:30 AM. At what time do they cross each other?

Solution:

The time gap between 6 AM-10 AM=4 hours

The time gap between 8 AM and 11:30 AM=3.5 hours

A B

T 4 3.5

S 3.5 4

Distance = Speed * Time = 4*3.5 = 14

In two hours A travel 7 km (2*3.5=7km)

At 8:56 both trains will meet.