Percentages Part 6

Based on marks

Problem 1: In an examination, Ram got 30% of the maximum marks and failed by 80 marks. Shyam got 200 marks and failed by 15%. Find the pass percentage marks in the exam?

Solution: Pass mark for Ram = 30%+80

The pass mark for Shyam = 200+15%

Both are pass mars we can equate these two

30%+80 = 200+15%

30%-15% = 200-80

15% = 120

100% = ?

\frac{120\times 100}{15} = 800

10% of 800 = 80

30%+10%=40%

The passing percentage is 40%

The pass mark is 800

Problem 2: A got 30% of the maximum marks and get failed by 25 marks whereas B gets 40% of the total marks in the same exam and set 25% of the passing mark more than the passing mark. Find the passing marks of the exam?

Solution: Let passing mark=pm

30%+25=pm

40%=\frac{pm\times 125}{100}

pm=32%

30%+25=32%

32%-30%=25

2%=25

Multiply with 16 on both sides so that we can get 32%

16*2%=25*16

32%=400

pm=32%=400

Problem 3: In an examination in which maximum marks are 500, A got 10% less than B. B got 25% more than C. C got 20% less than D. If A got 360 marks, What percentage of maximum marks was obtained by D?

Solution: Assume D=100

C got 20% less than D =  100\times \frac{80}{100}=80

B got 25% more than C = 80\times \frac{125}{100}=100

A got 10% less than B = 100\times \frac{90}{100}=90

90% \rightarrow 360

100%  \rightarrow ?

\frac{100\times 360}{90}=400

% of the maximum marks obtained by D is = \frac{400}{500}\times 100= 80%

Maximum marks obtained by D is = 400

 

 

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